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style: use the optional chains typescript-eslint 8.71 asks for #3797

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style: use the optional chains typescript-eslint 8.71 asks for #3797

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2 changes: 1 addition & 1 deletion src/app/app.module.ts
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Original file line number Diff line number Diff line change
Expand Up @@ -16,7 +16,7 @@ import { FirebaseApp, FirebaseApps } from './app';

export function defaultFirebaseAppFactory(provided: FirebaseApp[]|undefined) {
// Use the provided app, if there is only one, otherwise fetch the default app
if (provided && provided.length === 1) { return provided[0]; }
if (provided?.length === 1) { return provided[0]; }
return new FirebaseApp(getApp());
}

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2 changes: 1 addition & 1 deletion src/compat/firebase.app.module.ts
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Expand Up @@ -15,7 +15,7 @@ export function ɵfirebaseAppFactory(options: FirebaseOptions, zone: NgZone, nam
const config = typeof nameOrConfig === 'object' && nameOrConfig || {};
config.name = config.name || name;
// Added any due to some inconsistency between @firebase/app and firebase types
const existingApp = firebase.apps.find(app => app && app.name === config.name);
const existingApp = firebase.apps.find(app => app?.name === config.name);
// We support FirebaseConfig, initializeApp's public type only accepts string; need to cast as any
// Could be solved with https://github.com/firebase/firebase-js-sdk/pull/1206
const app = (existingApp || zone.runOutsideAngular(() => firebase.initializeApp(options, config as any)));
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